1.If (−4,5)(-4, 5)(−4,5) is one vertex and 7x−y+8=07x - y + 8 = 07x−y+8=0 is one diagonal of a square, then the equation of second diagonal isa.x+3y=21x + 3y = 21x+3y=21b.2x−3y=72x - 3y = 72x−3y=7c.x+7y=31x + 7y = 31x+7y=31d.2x+3y=212x + 3y = 212x+3y=21Login to continueOnly logged in users canattempt or see the solution.
