1.A body is projected vertically upwards at time t=0t = 0t=0 and it is seen at a height HHH at time t1t_1t1 and t2t_2t2 second during its flight. The maximum height attained is (ggg is acceleration due to gravity):a.g(t2−t1)28\frac{g(t_2 - t_1)^2}{8}8g(t2−t1)2b.g(t1+t2)24\frac{g(t_1 + t_2)^2}{4}4g(t1+t2)2c.g(t1+t2)28\frac{g(t_1 + t_2)^2}{8}8g(t1+t2)2d.g(t2−t1)24\frac{g(t_2 - t_1)^2}{4}4g(t2−t1)2Login to continueOnly logged in users canattempt or see the solution.