1.Given the following two statements:(S1):(∼q∨p)→(p⇔∼q)(S_1): (\sim q \vee p) \rightarrow (p \Leftrightarrow \sim q)(S1):(∼q∨p)→(p⇔∼q) is a tautology.(S2):∼q∧(∼p→q)(S_2): \sim q \wedge (\sim p \rightarrow q)(S2):∼q∧(∼p→q) is a fallacy.Then:a.both (S1)(S_1)(S1) and (S2)(S_2)(S2) are not correct.b.only (S1)(S_1)(S1) is correct.c.only (S2)(S_2)(S2) is correct.d.both (S1)(S_1)(S1) and (S2)(S_2)(S2) are correct.Login to continueOnly logged in users canattempt or see the solution.
