1.If tan−1(2x)+tan−1(3x)=π4\tan^{-1}(2x) + \tan^{-1}(3x) = \frac{\pi}{4}tan−1(2x)+tan−1(3x)=4π, where x>0x > 0x>0, then x=x =x=a.111b.16\frac{1}{6}61c.13\frac{1}{3}31d.12\frac{1}{2}21Login to continueOnly logged in users canattempt or see the solution.
