1.The equation of state for 5 g5\,\text{g}5g of oxygen at a pressure PPP and temperature TTT, when occupying a volume VVV, will be: (where RRR is the gas constant)a.PV=532RTPV = \frac{5}{32}RTPV=325RTb.PV=5RTPV = 5RTPV=5RTc.PV=52RTPV = \frac{5}{2}RTPV=25RTd.PV=516RTPV = \frac{5}{16}RTPV=165RTLogin to continueOnly logged in users canattempt or see the solution.
