1.The value of limx→1(x2−1)sin2(πx)x4−2x3+2x−1\lim_{x \to 1} \frac{(x^2 - 1)\sin^2(\pi x)}{x^4 - 2x^3 + 2x - 1}limx→1x4−2x3+2x−1(x2−1)sin2(πx) is equal to:Login to continueOnly logged in users canattempt or see the solution.
