1.A dielectric circular disc of radius RRR carries a uniform surface charge density σ\sigmaσ. If it rotates about its axis with angular velocity ω\omegaω, the magnetic field at the centre of disc is:a.μ0σωR22π\frac{\mu_0 \sigma \omega R^2}{2\pi}2πμ0σωR2b.μ0σωR2\frac{\mu_0 \sigma \omega R}{2}2μ0σωRc.μ0σωR24\frac{\mu_0 \sigma \omega R^2}{4}4μ0σωR2d.μ0σωR222\frac{\mu_0 \sigma \omega R^2}{2\sqrt{2}}22μ0σωR2Login to continueOnly logged in users canattempt or see the solution.