1.For a sequence (tn)(t_n)(tn), if Sn=5(2n−1)S_n = 5(2^n - 1)Sn=5(2n−1) then tn=…t_n = \dotstn=…a.5(2n+1)5(2n+1)5(2n+1)b.5×2n4\frac{5 \times 2^n}{4}45×2nc.5(2n−1)5(2^{n-1})5(2n−1)d.2×(2n−1)5\frac{2\times(2n-1)}{5}52×(2n−1)Login to continueOnly logged in users canattempt or see the solution.
