1.If tan2θ+tanθ1−tanθtan2θ=0\dfrac{\tan2\theta + \tan\theta}{1 - \tan\theta\tan2\theta} = 01−tanθtan2θtan2θ+tanθ=0, then the general value of θ\thetaθ isa.nπ, n∈In\pi,\; n \in Inπ,n∈Ib.nπ3, n∈I\dfrac{n\pi}{3},\; n \in I3nπ,n∈Ic.nπ4, n∈I\dfrac{n\pi}{4},\; n \in I4nπ,n∈Id.nπ2, n∈I\dfrac{n\pi}{2},\; n \in I2nπ,n∈ILogin to continueOnly logged in users canattempt or see the solution.
