1.ABABAB is a double ordinate of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2−b2y2=1 such that △AOB\triangle AOB△AOB (where OOO is the origin) is an equilateral triangle, then the eccentricity eee of the hyperbola satisfiesa.e>3e > \sqrt{3}e>3b.1<e<231 < e < \frac{2}{\sqrt{3}}1<e<32c.e=23e = \frac{2}{\sqrt{3}}e=32d.e>23e > \frac{2}{\sqrt{3}}e>32Login to continueOnly logged in users canattempt or see the solution.