1.Double ordinate PQPQPQ of x2/a2−y2/b2=1x^2/a^2-y^2/b^2=1x2/a2−y2/b2=1 with △OPQ\triangle OPQ△OPQ equilateral. Then eee satisfiesa.1<e<2/31<e<2/\sqrt{3}1<e<2/3b.e=2/3e=2/\sqrt{3}e=2/3c.e=3/2e=\sqrt{3}/2e=3/2d.e>2/3e>2/\sqrt{3}e>2/3Login to continueOnly logged in users canattempt or see the solution.