1.The solution of dydx−1=ex−y\frac{dy}{dx} - 1 = e^{x-y}dxdy−1=ex−y isa.ex−y+x=ce^{x-y} + x = cex−y+x=cb.e−(x−y)+x=ce^{-(x-y)} + x = ce−(x−y)+x=cc.e−(x−y)=x+ce^{-(x-y)} = x + ce−(x−y)=x+cd.ex−y=x+ce^{x-y} = x + cex−y=x+cLogin to continueOnly logged in users canattempt or see the solution.