1.Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimension of permeability isa.M−1LT−2AM^{-1}LT^{-2}AM−1LT−2Ab.ML2T−2A−1ML^2 T^{-2} A^{-1}ML2T−2A−1c.MLT−2A−2MLT^{-2} A^{-2}MLT−2A−2d.MLT−1A−1MLT^{-1} A^{-1}MLT−1A−1Login to continueOnly logged in users canattempt or see the solution.
