1.tan−1(−2)−tan−1(3)\tan^{-1}(-2) - \tan^{-1}(3)tan−1(−2)−tan−1(3) is equal toa.3π4\frac{3\pi}{4}43πb.−π6-\frac{\pi}{6}−6πc.π6\frac{\pi}{6}6πd.−3π4-\frac{3\pi}{4}−43πLogin to continueOnly logged in users canattempt or see the solution.
