1.Hyperbola through a focus of ellipse x2/169+y2/25=1x^2/169+y^2/25=1x2/169+y2/25=1, axes aligned, product of eccentricities =1=1=1. Its equation isa.x2/144−y2/9=1x^2/144 - y^2/9 = 1x2/144−y2/9=1b.x2/169−y2/25=1x^2/169 - y^2/25 = 1x2/169−y2/25=1c.x2/144−y2/25=1x^2/144 - y^2/25 = 1x2/144−y2/25=1d.x2/25−y2/9=1x^2/25 - y^2/9 = 1x2/25−y2/9=1Login to continueOnly logged in users canattempt or see the solution.
