1.Let f:R−{0}→Rf:\mathbb{R}-\{0\}\to\mathbb{R}f:R−{0}→R be a function such that f(x)−6f(1x)=35−5xf(x)-6f\left(\frac{1}{x}\right)=35-5xf(x)−6f(x1)=35−5x. If limx→0(α+xf(x))=β\lim_{x\to 0}(\alpha+xf(x))=\betalimx→0(α+xf(x))=β; α,β∈R\alpha,\beta\in\mathbb{R}α,β∈R, then α+2β\alpha+2\betaα+2β is equal to:Login to continueOnly logged in users canattempt or see the solution.
