1.CH3COOH \xrightarrow{LiAlH4} (A) \xrightarrow{I2/NaOH} (B) \xrightarrow{Ag(dust)} (C). Final product C:a.C2H5Ib.C2H5OHc.C2H2d.CH3COCH3Login to continueOnly logged in users canattempt or see the solution.
