1.If cos−1(2x2−1)=2π−2cos−1x\cos^{-1}(2x^2 - 1) = 2\pi - 2\cos^{-1} xcos−1(2x2−1)=2π−2cos−1x, thena.x∈[−1,0]x \in [-1, 0]x∈[−1,0]b.x∈[0,1]x \in [0, 1]x∈[0,1]c.x=0, 1/2x = 0,\; 1/2x=0,1/2d.x∈[−1,1]x \in [-1, 1]x∈[−1,1]Login to continueOnly logged in users canattempt or see the solution.
