1.Let B=(01−10)B = \begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix}B=(0−110) and AAA be a 2×22 \times 22×2 matrix such that A=B−1A = B^{-1}A=B−1. If BCB−1=ABCB^{-1} = ABCB−1=A and C2+αC+βI=0C^{2} + \alpha C + \beta I = 0C2+αC+βI=0, then 2β−α2\beta - \alpha2β−α is equal to:a.161616b.222c.888d.101010Login to continueOnly logged in users canattempt or see the solution.
