1.If A=[12−4−1]A = \begin{bmatrix} 1 & 2 \\ -4 & -1 \end{bmatrix}A=[1−42−1], then A−1A^{-1}A−1 isa.17[−1−241]\frac{1}{7} \begin{bmatrix} -1 & -2 \\ 4 & 1 \end{bmatrix}71[−14−21]b.17[12−4−1]\frac{1}{7} \begin{bmatrix} 1 & 2 \\ -4 & -1 \end{bmatrix}71[1−42−1]c.17[−1−24−1]\frac{1}{7} \begin{bmatrix} -1 & -2 \\ 4 & -1 \end{bmatrix}71[−14−2−1]d.Does not existLogin to continueOnly logged in users canattempt or see the solution.
