1.If f(x)={sin(p+1)x+sinxx,x<0q,x=03+x2−3x,x>0f(x) = \begin{cases} \frac{\sin(p+1)x + \sin x}{x}, & x < 0 \\ q, & x = 0 \\ \frac{\sqrt{3 + x^2} - \sqrt{3}}{x}, & x > 0 \end{cases}f(x)=⎩⎨⎧xsin(p+1)x+sinx,q,x3+x2−3,x<0x=0x>0 is continuous at x=0x = 0x=0, then the ordered pair (p,q)(p, q)(p,q) is equal to:a.(−32,0)\left(-\frac{3}{2}, 0\right)(−23,0)b.(−2,12)\left(-2, \frac{1}{2}\right)(−2,21)c.(2,12)\left(2, \frac{1}{2}\right)(2,21)d.(−2,0)(-2, 0)(−2,0)Login to continueOnly logged in users canattempt or see the solution.
