1.A wire in the form of a square of side aaa carries a current iii. Then, the magnetic induction at the centre of the square is (Magnetic permeability of free space = μ0\mu_0μ0)a.μ0i2πa\frac{\mu_0 i}{2\pi a}2πaμ0ib.μ0iπa2\frac{\mu_0 i}{\pi a \sqrt{2}}πa2μ0ic.22μ0iπa\frac{2\sqrt{2}\mu_0 i}{\pi a}πa22μ0id.μ0i2πa\frac{\mu_0 i}{\sqrt{2}\pi a}2πaμ0iLogin to continueOnly logged in users canattempt or see the solution.