1.On the basis of the following thermochemical data: (ΔfG∘H+(aq)=0\Delta_f G^\circ H^+(aq) = 0ΔfG∘H+(aq)=0)H2O(l)→H+(aq)+OH−(aq)H_2O(l) \rightarrow H^+(aq) + OH^-(aq)H2O(l)→H+(aq)+OH−(aq); ΔH=57.32\Delta H = 57.32ΔH=57.32 kJH2(g)+12O2(g)→H2O(l)H_2(g) + \frac{1}{2}O_2(g) \rightarrow H_2O(l)H2(g)+21O2(g)→H2O(l); ΔH=−286.20\Delta H = -286.20ΔH=−286.20 kJThe value of enthalpy of formation of OH−OH^-OH− ion at 25∘25^\circ25∘C is:a.−22.88-22.88−22.88 kJb.−228.88-228.88−228.88 kJc.+228.88+228.88+228.88 kJd.−343.52-343.52−343.52 kJLogin to continueOnly logged in users canattempt or see the solution.