1.Define f:R→Rf:\mathbb R\to\mathbb Rf:R→R by f(x)={(x−a)e1x−a−1e1x−a+1x≠a0x=af(x)=\begin{cases}(x-a)\frac{e^{\frac1{x-a}}-1}{e^{\frac1{x-a}}+1}&x\neq a\\0&x=a\end{cases}f(x)=⎩⎨⎧(x−a)ex−a1+1ex−a1−10x=ax=a. Then which is true?a.Left and right limits at x=ax=ax=a are equal and not equal to f(a)f(a)f(a)b.Both left and right limits exist and are not equalc.f(x)f(x)f(x) is continuous at x=ax=ax=ad.f(x)f(x)f(x) has a simple discontinuity at a point other than aaaLogin to continueOnly logged in users canattempt or see the solution.
