1.limn→∞1n[(n+1)(n+2)…(2n)]1/n=\displaystyle\lim_{n\to\infty}\frac1n[(n+1)(n+2)\ldots(2n)]^{1/n}=n→∞limn1[(n+1)(n+2)…(2n)]1/n=a.111b.000c.2/e2/e2/ed.4/e4/e4/eLogin to continueOnly logged in users canattempt or see the solution.
