1.Calculate ΔHf∘\Delta H_f^\circΔHf∘ for chloride ion from the following data:12H2(g)+12Cl2(g)→HCl(g)\frac{1}{2} H_2(g) + \frac{1}{2} Cl_2(g) \rightarrow HCl(g)21H2(g)+21Cl2(g)→HCl(g); ΔHf∘=−92.4\Delta H_f^\circ = -92.4ΔHf∘=−92.4 kJHCl(g)+nH2O→H+(aq)+Cl−(aq)HCl(g) + nH_2O \rightarrow H^+(aq) + Cl^-(aq)HCl(g)+nH2O→H+(aq)+Cl−(aq); ΔH=−74.8\Delta H = -74.8ΔH=−74.8 kJΔHf∘\Delta H_f^\circΔHf∘ of H+(aq)=0.0H^+(aq) = 0.0H+(aq)=0.0 kJa.−167.2-167.2−167.2 kJb.−165.2-165.2−165.2 kJc.−157.2-157.2−157.2 kJd.−147.2-147.2−147.2 kJLogin to continueOnly logged in users canattempt or see the solution.
