1.HBr reacts with CH2_22=CH−-−OCH3_33 under anhydrous conditions at room temperature to give:a.CH3_33CHO and CH3_33Brb.BrCH2_22CHO and CH3_33OHc.BrCH2_22CH2_22OCH3_33d.H3_33CCHBrOCH3_33Login to continueOnly logged in users canattempt or see the solution.
