1.Let E1E_1E1 and E2E_2E2 be two events such that the conditional probabilities P(E1∣E2)=12P(E_1 \mid E_2) = \dfrac{1}{2}P(E1∣E2)=21, P(E2∣E1)=12P(E_2 \mid E_1) = \dfrac{1}{2}P(E2∣E1)=21 and P(E1∩E2)=14P(E_1 \cap E_2) = \dfrac{1}{4}P(E1∩E2)=41. Then:a.P(E1∩E2′)=P(E1)⋅P(E2)P(E_1 \cap E_2') = P(E_1) \cdot P(E_2)P(E1∩E2′)=P(E1)⋅P(E2)b.P(E1′∩E2)=P(E1)⋅P(E2′)P(E_1' \cap E_2) = P(E_1) \cdot P(E_2')P(E1′∩E2)=P(E1)⋅P(E2′)c.P(E1∩E2)=P(E1)⋅P(E2)P(E_1 \cap E_2) = P(E_1) \cdot P(E_2)P(E1∩E2)=P(E1)⋅P(E2)d.P(E1∪E2)=P(E1)⋅P(E2)P(E_1 \cup E_2) = P(E_1) \cdot P(E_2)P(E1∪E2)=P(E1)⋅P(E2)Login to continueOnly logged in users canattempt or see the solution.
