1.The dimensions of ab\frac{a}{b}ba, in the equation P=a−t2bxP = \frac{a - t^2}{b x}P=bxa−t2, where PPP is pressure, xxx is distance and ttt is time, area.[M2LT−3][M^2 LT^{-3}][M2LT−3]b.[MT−2][MT^{-2}][MT−2]c.[ML3T−1][ML^3T^{-1}][ML3T−1]d.[LT−3][LT^{-3}][LT−3]Login to continueOnly logged in users canattempt or see the solution.
