1.The value of the integral ∫0π/2log(sinx) dx\int_0^{\pi/2} \log(\sin x)\,dx∫0π/2log(sinx)dx isa.−π2log2-\frac{\pi}{2}\log 2−2πlog2b.−πlog2-\pi\log 2−πlog2c.π2log2\frac{\pi}{2}\log 22πlog2d.πlog2\pi\log 2πlog2Login to continueOnly logged in users canattempt or see the solution.
