1.The eccentricity of ellipse x216+y27=1\frac{x^2}{16}+\frac{y^2}{7}=116x2+7y2=1 isa.34\frac{3}{4}43b.54\frac{5}{4}45c.74\frac{\sqrt{7}}{4}47d.72\frac{\sqrt{7}}{2}27Login to continueOnly logged in users canattempt or see the solution.
