1.The mass of Na3PO4\mathrm{Na_3PO_4}Na3PO4 that should be added to 10 L10\,\mathrm{L}10L of 1.0×10−5 M1.0 \times 10^{-5}\,\mathrm{M}1.0×10−5M BaCl2\mathrm{BaCl_2}BaCl2 solution without any precipitation of Ba3(PO4)2\mathrm{Ba_3(PO_4)_2}Ba3(PO4)2 is [KspK_{sp}Ksp of Ba3(PO4)2=4×10−23\mathrm{Ba_3(PO_4)_2} = 4 \times 10^{-23}Ba3(PO4)2=4×10−23]a.2×10−4 g2 \times 10^{-4}\,\mathrm{g}2×10−4gb.0.328 g0.328\,\mathrm{g}0.328gc.0.164 g0.164\,\mathrm{g}0.164gd.0.82 g0.82\,\mathrm{g}0.82gLogin to continueOnly logged in users canattempt or see the solution.
