1.p,qp,qp,q for cont at 000a.p=1/2,q=e2/3p=1/2,q=e^{2/3}p=1/2,q=e2/3b.p=0,q=e2/3p=0,q=e^{2/3}p=0,q=e2/3c.p=1/2,q=e−2/3p=1/2,q=e^{-2/3}p=1/2,q=e−2/3d.p=−1/2,q=e2/3p=-1/2,q=e^{2/3}p=−1/2,q=e2/3Login to continueOnly logged in users canattempt or see the solution.
