1.Calculate the mean free path in CO2\text{CO}_2CO2 at 27°C27\degree\text{C}27°C and a pressure of 10−9 bar10^{-9}\,\text{bar}10−9bar.[molecular diameter =500 pm= 500\,\text{pm}=500pm][Given: R=253 J mol−1 K−1R = \dfrac{25}{3}\,\text{J}\,\text{mol}^{-1}\,\text{K}^{-1}R=325Jmol−1K−1; 2=1.4\sqrt{2} = 1.42=1.4; π=227\pi = \dfrac{22}{7}π=722; NA=6×1023N_A = 6 \times 10^{23}NA=6×1023]a.3.78×105 cm3.78 \times 10^{5}\,\text{cm}3.78×105cmb.3.78×104 cm3.78 \times 10^{4}\,\text{cm}3.78×104cmc.3.78×103 cm3.78 \times 10^{3}\,\text{cm}3.78×103cmd.6.78×103 cm6.78 \times 10^{3}\,\text{cm}6.78×103cmLogin to continueOnly logged in users canattempt or see the solution.
