1.Four particles, each of mass MMM move along a circle of radius RRR under the action of their mutual gravitational attraction. The speed of each particle is:a.GMR\sqrt{\frac{GM}{R}}RGMb.12GMR(1+22)\frac{1}{2}\sqrt{\frac{GM}{R}(1+2\sqrt{2})}21RGM(1+22)c.12GMR(1+22)\frac{1}{2}\sqrt{\frac{GM}{R}(1+2\sqrt{2})}21RGM(1+22)d.12GMR(1+22)\frac{1}{2}\sqrt{\frac{GM}{R}(1+2\sqrt{2})}21RGM(1+22)Login to continueOnly logged in users canattempt or see the solution.