1.If the sum of the first 202020 terms of the series log(71/2)+log(71/3)+log(71/4)+…\log(7^{1/2}) + \log(7^{1/3}) + \log(7^{1/4}) + \dotslog(71/2)+log(71/3)+log(71/4)+… is 460460460, then xxx is equal to:a.727^272b.71/27^{1/2}71/2c.e2e^2e2d.746/217^{46/21}746/21Login to continueOnly logged in users canattempt or see the solution.
