1.If e1e_1e1 and e2e_2e2 represent the eccentricity of 16x2−9y2=14416x^2 - 9y^2 = 14416x2−9y2=144 and 9x2−16y2=1449x^2 - 16y^2 = 1449x2−16y2=144 respectively. Then 1e12+1e22\frac{1}{e_1^2} + \frac{1}{e_2^2}e121+e221 isa.0b.1c.2d.3Login to continueOnly logged in users canattempt or see the solution.