1.The general solution of dydx=x+7y+33x+5y+9\frac{dy}{dx} = \frac{x+7y+3}{3x+5y+9}dxdy=3x+5y+9x+7y+3 isa.(x−3)4(y−x+3)4=c(5y+x−3)5(x-3)^4(y-x+3)^4 = c(5y+x-3)^5(x−3)4(y−x+3)4=c(5y+x−3)5b.(x+3)4(y−x−3)4=c(5y+x+3)5(x+3)^4(y-x-3)^4 = c(5y+x+3)^5(x+3)4(y−x−3)4=c(5y+x+3)5c.(y−x+3)4=c∣5y+x−3∣(y-x+3)^4 = c|5y+x-3|(y−x+3)4=c∣5y+x−3∣d.(y−x+3)4=c∣5y+x+3∣(y-x+3)^4 = c|5y+x+3|(y−x+3)4=c∣5y+x+3∣Login to continueOnly logged in users canattempt or see the solution.
