1.The statement (p∧(p⇒q)∧(q⇒r))⇒r(p \wedge (p \Rightarrow q) \wedge (q \Rightarrow r)) \Rightarrow r(p∧(p⇒q)∧(q⇒r))⇒r is:a.a tautologyb.equivalent to q⇒rq \Rightarrow rq⇒rc.a fallacyd.equivalent to p⇒∼rp \Rightarrow \sim rp⇒∼rLogin to continueOnly logged in users canattempt or see the solution.
