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Given P(x)=x4+ax3+bx2+cx+dP(x) = x^4 + ax^3 + bx^2 + cx + d such that x=0x = 0 is the only real root of P(x)=0P'(x) = 0. If P(1)<P(1)P(-1) < P(1), then in the interval [1,1][-1, 1]
Limit, Continuity and Differentiability - Hard - Question