1.If the lines 3x−4y−7=03x-4y-7=03x−4y−7=0 and 2x−3y−5=02x-3y-5=02x−3y−5=0 pass through diameters of a circle of area 49π49\pi49π sq units, then its equation isa.x2+y2−2x+2y−47=0x^2+y^2-2x+2y-47=0x2+y2−2x+2y−47=0b.x2+y2+2x−2y−51=0x^2+y^2+2x-2y-51=0x2+y2+2x−2y−51=0c.x2+y2−2x+2y+51=0x^2+y^2-2x+2y+51=0x2+y2−2x+2y+51=0d.x2+y2+2x+2y+47=0x^2+y^2+2x+2y+47=0x2+y2+2x+2y+47=0Login to continueOnly logged in users canattempt or see the solution.
