What mass of 95\% pure $\text{CaCO}_3$ will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?

$\text{CaCO}_3(s) + 2\text{HCl}(aq) \rightarrow \text{CaCl}_2(aq) + \text{CO}_2(g) + \text{H}_2\text{O}(l)$

[Calculate upto second place of decimal point]