1.Area of quadrilateral formed by joining foci of x29+y25=1\frac{x^2}{9}+\frac{y^2}{5}=19x2+5y2=1 and x25+y29=1\frac{x^2}{5}+\frac{y^2}{9}=15x2+9y2=1 isa.444b.222c.666d.888Login to continueOnly logged in users canattempt or see the solution.