A simple pendulum of length $1\,\text{m}$ and having a bob of mass $100\,\text{g}$ is suspended in a car, moving on a circular track of radius $100\,\text{m}$ with uniform speed $10\,\text{m/s}$. If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T = 2\pi/\alpha^{1/4}$. The value of $\alpha$ is [Take $g = 10\,\text{m/s}^2$]