1.Let AAA be a 2×22 \times 22×2 matrix with det(A)=−1\det(A) = -1det(A)=−1 and det((A+I)(adj(A)+I))=4\det\bigl((A + I)(\text{adj}(A) + I)\bigr) = 4det((A+I)(adj(A)+I))=4. Then the sum of the diagonal elements of AAA can be:a.−1-1−1b.222c.111d.−2-\sqrt{2}−2Login to continueOnly logged in users canattempt or see the solution.
