1.If x2=∣−cosθsinθ0cosθsinθ1sinθcosθ2∣x^2 = \begin{vmatrix} -\cos\theta & \sin\theta & 0 \\ \cos\theta & \sin\theta & 1 \\ \sin\theta & \cos\theta & 2 \end{vmatrix}x2=−cosθcosθsinθsinθsinθcosθ012, then the value of 4x2+xsinπ4+54x^2 + x\sin\frac{\pi}{4} + 54x2+xsin4π+5 isa.13−213 - \sqrt{2}13−2b.13+213 + \sqrt{2}13+2c.2−13\sqrt{2} - 132−13d.Both (A) and (B)Login to continueOnly logged in users canattempt or see the solution.
