1.(p⇒r)⇔(p∧¬q)(p \Rightarrow r) \Leftrightarrow (p \wedge \neg q)(p⇒r)⇔(p∧¬q) is equivalent to ¬p\neg p¬p when rrr is:a.pppb.¬p\neg p¬pc.qqqd.¬q\neg q¬qLogin to continueOnly logged in users canattempt or see the solution.
