1.
For a suitably chosen real constant aa, let a function f:R−{−a}→Rf: \mathbb{R} - \{-a\} \to \mathbb{R} be defined by f(x)=a−xa+xf(x) = \frac{a-x}{a+x}. Further suppose that for any real number x≠−ax \neq -a and f(x)≠−af(x) \neq -a, (f∘f)(x)=x(f \circ f)(x) = x. Then f(−12)f\left(-\frac{1}{2}\right) is equal to: