1.When an electron revolving in the ground state of a hydrogen atom jumps to its 2nd excited state,Note: More than one option may be correct.a.Its frequency of revolution becomes 827\dfrac{8}{27}278 timesb.Its frequency of revolution becomes (8/27)−3(8/27)^{-3}(8/27)−3 timesc.Its speed becomes 13\dfrac{1}{3}31 timesd.Its speed becomes 14\dfrac{1}{4}41 timesLogin to continueOnly logged in users canattempt or see the solution.