1.If y=y(x),x∈(0,π/2)y = y(x), x\in(0,\pi/2)y=y(x),x∈(0,π/2) be the solution curve of the DE (sin22x)dydx+(8sin22x+2sin4x)y=2e−4x(2sin2x+cos2x)(\sin^2 2x)\frac{dy}{dx} + (8\sin^2 2x + 2\sin 4x)y = 2e^{-4x}(2\sin 2x + \cos 2x)(sin22x)dxdy+(8sin22x+2sin4x)y=2e−4x(2sin2x+cos2x), with y(π/4)=e−πy(\pi/4) = e^{-\pi}y(π/4)=e−π, then y(π/6)y(\pi/6)y(π/6) is equal toa.23e−2π/3\frac{2}{\sqrt{3}} e^{-2\pi/3}32e−2π/3b.23e2π/3\frac{2}{\sqrt{3}} e^{2\pi/3}32e2π/3c.13e−2π/3\frac{1}{\sqrt{3}} e^{-2\pi/3}31e−2π/3d.13e2π/3\frac{1}{\sqrt{3}} e^{2\pi/3}31e2π/3Login to continueOnly logged in users canattempt or see the solution.
